TCM 1 736-(R) – Johann Maier & Co. – Stuttgart (DE) PQ299

2 Replies to “TCM 1 736-(R) – Johann Maier & Co. – Stuttgart (DE) PQ299”

1. QTR-EN-2549D060022F-_-Issue-01_V3

   Code D: split pin (cotter pin hole in threaded area)
   F: TR 4070 code F (lubricant)
   MJ6x1,00
   022 : shank length (threaded length not included)

   Fatigue test:
   As per “Minutes of 3rd ASD-CERT Mechanical Workshop 2019, February 12th”, clause E, we have: “E.G. Part Bolt EN2549 (with grip length > 2D nom) shall be Tension Fatigue Strength tested for code op-tions: H (lockwire holes in the head), D (Split pin hole in the threaded shank), C (Both Lockwire & Split Pin holes) & – (no holes).”
   In this QTR, it is written, for tension fatigue test: “Applicable only for bolts without hole”.
   ISO9152 states, for tension fatigue test applicability conditions: “d) drilled shank bolts;”.
   These bolts have split pin holes in threaded length, not shank length (I mean, smooth length under head bolt, not threaded).
   So, in my opinion, tension fatigue test on EN2549D060022F bolt shall be done since grip length is long enough and the hole is not located in shank area, but in threaded area.
   “The hole position shall be intended for use in the bolt thread protrusion zone clear of the fully seated nut”.
   QTP shall be updated in the same way on this topic.

   Clause 3.3.2: heat treatment:
   Raw material is a bar of approx. 7 mm in diameter.
   After solution heat treatment, quenching in water and tempering, we should have the following requirements for tensile test on specimens (as per WL 3.7164.7 for bars with diameter lower than or equal to 13 mm): Rm ? 1100 MPa, Rp0,2 ? 1030 MPa.
   In QTR, clause 3.3.2, we have:
   Tensile strength Rm 1070 MPa
   Yield Strength Rp 0,2 1000 MPa
   Moreover, in QTR page 20, we have Rm ? 1100 MPa, Rp0,2 ? 1030 MPa requirements for 3.7164.7 raw material (bar Ø 7 mm).
   QTP shall be updated in the same way on this topic.

   Page 9, 28 and 30 – thread major diameter.
   As per EN2549, Table 1, note a, thread major diameter “d max” shall be equal to D1min – 0,025.
   D1min = 6 – 0,022 = 5,978 mm
   d max = 5,978 – 0,025 = 5,953 mm instead of 6,000 mm.
   Actual values measured for major diameter are in line with d max = 5,953 mm if I am not mistaken, but the right d max shall be implemented for another production batches.
   QTP shall be updated in the same way on this topic.

   Many thanks in advance and have a good day.
   Regards, Julien

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2. Dear Heinrich,

   Qualification approved on my side based on “RE ASD-Cert Qualification Nr. PQ299; 736 (706)” pdf file attached.
   Many thanks and have a nice weekend.
   Regards, Julien

   Reply